Oracle Database Programming with SQL Section 8
1. If you want to include subtotals and grand totals for all columns mentioned in a GROUP BY clause, you should use which of the following extensions to the GROUP BY clause?
♦HAVING
♦ROLLUP
♦CUBE (*)
♦GROUP BY ALL COLUMNS
♦ROLLUP
♦CUBE (*)
♦GROUP BY ALL COLUMNS
2. Examine the following statement:
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY GROUPING SETS((department_id, manager_id), (department_id, job_id))
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY GROUPING SETS((department_id, manager_id), (department_id, job_id))
What data will this query generate?
♦Sum of salaries for (department_id, job_id) and (department_id, manager_id) (*)
♦Sum of salaries for (department_id, job_id, manager_id)
♦Subtotals for (job_id, manager_id)
♦The statement will fail.
♦Sum of salaries for (department_id, job_id, manager_id)
♦Subtotals for (job_id, manager_id)
♦The statement will fail.
3. Examine the following statement:
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY ROLLUP(department_id, manager_id)
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY ROLLUP(department_id, manager_id)
What extra data will this query generate?
♦Subtotals for department_id, and grand totals for salary
♦Subtotals for department_id, job_id and grand totals for salary
♦Subtotals for department_id, job_id, manager_id and grand totals for salary
♦The statement will fail. (*)
♦Subtotals for department_id, job_id and grand totals for salary
♦Subtotals for department_id, job_id, manager_id and grand totals for salary
♦The statement will fail. (*)
4. You use ROLLUP to:
♦produce subtotal values (*)
♦cross-tabulate values
♦produce a single result set
♦cross-tabulate values
♦produce a single result set
5. CUBE will cross-reference the columns listed in the ______ clause to create a superset of groups.
♦GROUP BY (*)
♦WHERE
♦SELECT
♦WHERE
♦SELECT
6. CUBE can be applied to all aggregate functions including AVG, SUM, MIN, MAX, and COUNT. True or False?
♦True (*)
♦False
♦False
7. Which of the following are correct SET operators? (choose two) (Choose all correct answers)
♦MINUS, PLUS
♦UNION, MINUS (*)
♦UNION ALL, PLUS ALL
♦UNION ALL, INTERSECT (*)
♦MINUS, PLUS
♦UNION, MINUS (*)
♦UNION ALL, PLUS ALL
♦UNION ALL, INTERSECT (*)
8. The ___________ operator returns all rows from both tables, after eliminating duplicates.
♦UNION ALL
♦UNION (*)
♦MINUS
♦INTERSECT
♦UNION ALL
♦UNION (*)
♦MINUS
♦INTERSECT
9. To control the order of rows returned using SET operators, the ORDER BY clause is used ______ and is placed in the _____ SELECT statement of the query.
♦ONCE; LAST (*)
♦IN ALL; LAST
♦ONCE; FIRST
♦TWICE; FIRST
♦ONCE; LAST (*)
♦IN ALL; LAST
♦ONCE; FIRST
♦TWICE; FIRST
10. If a select list contains both a column as well as a group function then what clause is required?
♦HAVING clause
♦GROUP BY clause (*)
♦ORDER BY clause
♦JOIN clause
♦HAVING clause
♦GROUP BY clause (*)
♦ORDER BY clause
♦JOIN clause
11. Is the following statement correct?
SELECT first_name, last_name, salary, department_id, COUNT(employee_id)
FROM employees
WHERE department_id = 50
GROUP BY last_name, first_name, department_id;
SELECT first_name, last_name, salary, department_id, COUNT(employee_id)
FROM employees
WHERE department_id = 50
GROUP BY last_name, first_name, department_id;
♦Yes
♦No, because the statement is missing salary in the GROUP BY clause (*)
♦Yes, because Oracle will correct any mistakes in the statement itself
♦No, beause you cannot have a WHERE-clause when you use group functions.
♦No, because the statement is missing salary in the GROUP BY clause (*)
♦Yes, because Oracle will correct any mistakes in the statement itself
♦No, beause you cannot have a WHERE-clause when you use group functions.
12. What will the following SQL Statement do?
SELECT job_id, COUNT(*)
FROM employees
GROUP BY job_id;
SELECT job_id, COUNT(*)
FROM employees
GROUP BY job_id;
♦Displays each job id and the number of people assigned to that job id (*)
♦Displays all the jobs with as many people as there are jobs
♦Displays only the number of job_ids
♦Displays all the employees and groups them by job
♦Displays all the jobs with as many people as there are jobs
♦Displays only the number of job_ids
♦Displays all the employees and groups them by job
13. The PLAYERS table contains these columns:
PLAYER_ID NUMBER PK
PLAYER_NAME VARCHAR2 (30)
TEAM_ID NUMBER
HIRE_DATE DATE
SALARY NUMBER (8,2)
PLAYER_ID NUMBER PK
PLAYER_NAME VARCHAR2 (30)
TEAM_ID NUMBER
HIRE_DATE DATE
SALARY NUMBER (8,2)
Which clauses represent valid uses of aggregate functions? (Choose three.)
(Choose all correct answers)
♦SELECT AVG(NVL(salary, 0)) (*)
♦GROUP BY MAX(salary)
♦ORDER BY AVG(salary) (*)
♦WHERE hire_date > AVG(hire_date)
♦HAVING MAX(salary) > 10000 (*)
♦SELECT AVG(NVL(salary, 0)) (*)
♦GROUP BY MAX(salary)
♦ORDER BY AVG(salary) (*)
♦WHERE hire_date > AVG(hire_date)
♦HAVING MAX(salary) > 10000 (*)
14. Evaluate this SELECT statement:
SELECT MIN(hire_date), department_id
FROM employees
GROUP BY department_id;
SELECT MIN(hire_date), department_id
FROM employees
GROUP BY department_id;
Which values are displayed?
♦The hire dates in the EMPLOYEES table that contain NULL values
♦The latest hire date in the EMPLOYEES table
♦The earliest hire date in each department (*)
♦The earliest hire date in the EMPLOYEES table
♦The latest hire date in the EMPLOYEES table
♦The earliest hire date in each department (*)
♦The earliest hire date in the EMPLOYEES table
15. The EMPLOYEES table contains these columns:
ID_NUMBER NUMBER Primary Key
NAME VARCHAR2 (30)
DEPARTMENT_ID NUMBER
SALARY NUMBER (7,2)
HIRE_DATE DATE
ID_NUMBER NUMBER Primary Key
NAME VARCHAR2 (30)
DEPARTMENT_ID NUMBER
SALARY NUMBER (7,2)
HIRE_DATE DATE
Evaluate this SQL statement:
SELECT id_number, name, department_id, SUM(salary)
FROM employees
WHERE salary > 25000
GROUP BY department_id, id_number, name
ORDER BY hire_date;
FROM employees
WHERE salary > 25000
GROUP BY department_id, id_number, name
ORDER BY hire_date;
Why will this statement cause an error?
♦The HAVING clause is missing.
♦The SALARY column is NOT included in the GROUP BY clause.
♦The WHERE clause contains a syntax error.
♦The HIRE_DATE column is NOT included in the GROUP BY clause. (*)
♦The SALARY column is NOT included in the GROUP BY clause.
♦The WHERE clause contains a syntax error.
♦The HIRE_DATE column is NOT included in the GROUP BY clause. (*)
16. Which statement about group functions is true?
♦Group functions can only be used in a SELECT list.
♦A query that includes a group function in the SELECT list must include a GROUP BY clause.
♦Group functions ignore null values. (*)
♦Group functions can be used in a WHERE clause.
♦Group functions can only be used in a SELECT list.
♦A query that includes a group function in the SELECT list must include a GROUP BY clause.
♦Group functions ignore null values. (*)
♦Group functions can be used in a WHERE clause.
17. What is the best explanation as to why this SQL statement will NOT execute?
SELECT department_id “Department”, AVG (salary)”Average”
FROM employees
GROUP BY Department;
SELECT department_id “Department”, AVG (salary)”Average”
FROM employees
GROUP BY Department;
♦The GROUP BY clause must have something to GROUP.
♦Salaries cannot be averaged as not all the numbers will divide evenly.
♦You cannot use a column alias in the GROUP BY clause. (*)
♦The department id is not listed in the departments table.
♦Salaries cannot be averaged as not all the numbers will divide evenly.
♦You cannot use a column alias in the GROUP BY clause. (*)
♦The department id is not listed in the departments table.
18. The PRODUCTS table contains these columns:
PROD_ID NUMBER(4)
PROD_NAME VARCHAR(20)
PROD_CAT VARCHAR2(15)
PROD_PRICE NUMBER(5)
PROD_QTY NUMBER(4)
PROD_ID NUMBER(4)
PROD_NAME VARCHAR(20)
PROD_CAT VARCHAR2(15)
PROD_PRICE NUMBER(5)
PROD_QTY NUMBER(4)
You need to identify the minimum product price in each product category.
Which statement could you use to accomplish this task?
Which statement could you use to accomplish this task?
♦SELECT prod_price, MIN (prod_cat)
FROM products
GROUP BY prod_cat;
FROM products
GROUP BY prod_cat;
♦SELECT prod_cat, MIN (prod_price)
FROM products
GROUP BY prod_price;
FROM products
GROUP BY prod_price;
♦SELECT prod_cat, MIN (prod_price)
FROM products
GROUP BY prod_cat;
(*)
FROM products
GROUP BY prod_cat;
(*)
♦SELECT MIN (prod_price), prod_cat
FROM products
GROUP BY MIN (prod_price), prod_cat;
FROM products
GROUP BY MIN (prod_price), prod_cat;
19. Evaluate this statement:
SELECT department_id, AVG(salary)
FROM employees
WHERE job_id <> 69879
GROUP BY job_id, department_id
HAVING AVG(salary) > 35000
ORDER BY department_id;
SELECT department_id, AVG(salary)
FROM employees
WHERE job_id <> 69879
GROUP BY job_id, department_id
HAVING AVG(salary) > 35000
ORDER BY department_id;
Which clauses restricts the result? Choose two.
(Choose all correct answers)
♦GROUP BY job_id, department_id
♦WHERE job_id <> 69879 (*)
♦SELECT department_id, AVG(salary)
♦HAVING AVG(salary) > 35000 (*)
♦WHERE job_id <> 69879 (*)
♦SELECT department_id, AVG(salary)
♦HAVING AVG(salary) > 35000 (*)
20. The PRODUCTS table contains these columns:
PRODUCT_ID NUMBER(9) PK
CATEGORY_ID VARCHAR2(10)
LOCATION_ID NUMBER(9)
DESCRIPTION VARCHAR2(30)
COST NUMBER(7,2)
PRICE NUMBER(7,2)
QUANTITY NUMBER
PRODUCT_ID NUMBER(9) PK
CATEGORY_ID VARCHAR2(10)
LOCATION_ID NUMBER(9)
DESCRIPTION VARCHAR2(30)
COST NUMBER(7,2)
PRICE NUMBER(7,2)
QUANTITY NUMBER
You display the total of the extended costs for each product category by location.
You need to include only the products that have a price less than $25.00.
The extended cost of each item equals the quantity value multiplied by the cost value.
Which SQL statement will display the desired result?
You need to include only the products that have a price less than $25.00.
The extended cost of each item equals the quantity value multiplied by the cost value.
Which SQL statement will display the desired result?
♦SELECT SUM(cost * quantity) TOTAL
FROM products
WHERE price < 25.00;
FROM products
WHERE price < 25.00;
♦SELECT category_id, SUM(cost * quantity) TOTAL,location_id
FROM products
WHERE price > 25.00
GROUP BY category_id, location_id;
FROM products
WHERE price > 25.00
GROUP BY category_id, location_id;
♦SELECT SUM(cost * quantity) TOTAL, location_id
FROM products
WHERE price < 25.00
GROUP BY location_id;
FROM products
WHERE price < 25.00
GROUP BY location_id;
♦SELECT category_id, SUM(cost * quantity) TOTAL, location_id
FROM products
WHERE price < 25.00
GROUP BY category_id, location_id;
(*)
FROM products
WHERE price < 25.00
GROUP BY category_id, location_id;
(*)
21. Evaluate this SELECT statement:
SELECT COUNT(employee_id), department_id
FROM employees
GROUP BY department_id;
SELECT COUNT(employee_id), department_id
FROM employees
GROUP BY department_id;
You only want to include employees who earn more than 15000.
Which clause should you include in the SELECT statement?
Which clause should you include in the SELECT statement?
♦HAVING salary > 15000
♦HAVING SUM(salary) > 15000
♦WHERE salary > 15000 (*)
♦WHERE SUM(salary) > 15000
♦HAVING SUM(salary) > 15000
♦WHERE salary > 15000 (*)
♦WHERE SUM(salary) > 15000
22. You use GROUPING functions to:
♦Produce subtotal and cross-tabulated values
♦Identify the extra row values created by either a ROLLUP or CUBE operation (*)
♦Aggregate rows using SUM, MIN, MAX, and COUNT
♦Identify the extra row values created by either a ROLLUP or CUBE operation (*)
♦Aggregate rows using SUM, MIN, MAX, and COUNT
23. Examine the following statement:
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY GROUPING SETS((department_id, manager_id), (department_id, job_id))
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY GROUPING SETS((department_id, manager_id), (department_id, job_id))
What data will this query generate?
♦Sum of salaries for (department_id, job_id) and (department_id, manager_id) (*)
♦Sum of salaries for (department_id, job_id, manager_id)
♦Subtotals for (job_id, manager_id)
♦The statement will fail.
♦Sum of salaries for (department_id, job_id, manager_id)
♦Subtotals for (job_id, manager_id)
♦The statement will fail.
24. CUBE will cross-reference the columns listed in the ______ clause to create a superset of groups.
♦SELECT
♦GROUP BY (*)
♦WHERE
♦SELECT
♦GROUP BY (*)
♦WHERE
25. You use ROLLUP to:
♦cross-tabulate values
♦produce subtotal values (*)
♦produce a single result set
♦produce subtotal values (*)
♦produce a single result set
26. GROUPING SETS is another extension to the GROUP BY clause and is used to specify multiple groupings of data but provide a single result set. True or False?
♦True (*)
♦False
♦False
27. If you want to include subtotals and grand totals for all columns mentioned in a GROUP BY clause, you should use which of the following extensions to the GROUP BY clause?
♦ROLLUP
♦GROUP BY ALL COLUMNS
♦HAVING
♦CUBE (*)
♦GROUP BY ALL COLUMNS
♦HAVING
♦CUBE (*)
28. Which of the following are correct SET operators? (choose two)
(Choose all correct answers)
♦UNION, MINUS (*)
♦UNION ALL, PLUS ALL
♦MINUS, PLUS
♦UNION ALL, INTERSECT (*)
(Choose all correct answers)
♦UNION, MINUS (*)
♦UNION ALL, PLUS ALL
♦MINUS, PLUS
♦UNION ALL, INTERSECT (*)
29. The difference between UNION and UNION ALL is
♦There is no difference; you get exactly the same result from both.
♦UNION ALL is more like a NATURAL JOIN.
♦UNION will remove duplicates; UNION ALL returns all rows from all queries including the duplicates. (*)
♦UNION is a synomym for UNION ALL.
♦UNION ALL is more like a NATURAL JOIN.
♦UNION will remove duplicates; UNION ALL returns all rows from all queries including the duplicates. (*)
♦UNION is a synomym for UNION ALL.
30. When using SET operators, the names of the matching columns must be identical in all of the SELECT statements used in the query. True or False?
♦True
♦False (*)
♦False (*)
31. How would you alter the following query to list only employees where two or more employees have the same last name?
SELECT last_name, COUNT(employee_id)
FROM EMPLOYEES
GROUP BY last_name;
SELECT last_name, COUNT(employee_id)
FROM EMPLOYEES
GROUP BY last_name;
♦SELECT last_name, COUNT(employee_id)
FROM EMPLOYEES
WHERE COUNT(*) > 1
GROUP BY last_name
FROM EMPLOYEES
WHERE COUNT(*) > 1
GROUP BY last_name
♦SELECT last_name, COUNT(last_name)
FROM EMPLOYEES
GROUP BY last_name
HAVING COUNT(last_name) > 1;
(*)
FROM EMPLOYEES
GROUP BY last_name
HAVING COUNT(last_name) > 1;
(*)
♦SELECT last_name, COUNT(last_name)
FROM EMPLOYEES
GROUP BY last_name
EXISTS COUNT(last_name) > 1;
FROM EMPLOYEES
GROUP BY last_name
EXISTS COUNT(last_name) > 1;
♦SELECT employee_id, DISTINCT(last_name)
FROM EMPLOYEES
GROUP BY last_name
HAVING last_name > 1;
FROM EMPLOYEES
GROUP BY last_name
HAVING last_name > 1;
32. Which statement about the GROUP BY clause is true?
♦To exclude rows before dividing them into groups using the GROUP BY clause, you should use a WHERE clause. (*)
♦You can use a column alias in a GROUP BY clause.
♦You must use the HAVING clause with the GROUP BY clause.
♦By default, rows are not sorted when a GROUP BY clause is used.
♦You must use the HAVING clause with the GROUP BY clause.
♦By default, rows are not sorted when a GROUP BY clause is used.
33. The PRODUCTS table contains these columns:
PRODUCT_ID NUMBER(9) PK
CATEGORY_ID VARCHAR2(10)
LOCATION_ID NUMBER(9)
DESCRIPTION VARCHAR2(30)
COST NUMBER(7,2)
PRICE NUMBER(7,2)
QUANTITY NUMBER
PRODUCT_ID NUMBER(9) PK
CATEGORY_ID VARCHAR2(10)
LOCATION_ID NUMBER(9)
DESCRIPTION VARCHAR2(30)
COST NUMBER(7,2)
PRICE NUMBER(7,2)
QUANTITY NUMBER
You display the total of the extended costs for each product category by location.
You need to include only the products that have a price less than $25.00.
The extended cost of each item equals the quantity value multiplied by the cost value.
Which SQL statement will display the desired result?
You need to include only the products that have a price less than $25.00.
The extended cost of each item equals the quantity value multiplied by the cost value.
Which SQL statement will display the desired result?
♦SELECT SUM(cost * quantity) TOTAL, location_id
FROM products
WHERE price < 25.00
GROUP BY location_id;
FROM products
WHERE price < 25.00
GROUP BY location_id;
♦SELECT category_id, SUM(cost * quantity) TOTAL,location_id
FROM products
WHERE price > 25.00
GROUP BY category_id, location_id;
FROM products
WHERE price > 25.00
GROUP BY category_id, location_id;
♦SELECT category_id, SUM(cost * quantity) TOTAL, location_id
FROM products
WHERE price < 25.00
GROUP BY category_id, location_id;
(*)
FROM products
WHERE price < 25.00
GROUP BY category_id, location_id;
(*)
♦SELECT SUM(cost * quantity) TOTAL
FROM products
WHERE price < 25.00;
FROM products
WHERE price < 25.00;
34. Evaluate this SELECT statement:
SELECT SUM(salary), department_id, manager_id
FROM employees
GROUP BY department_id, manager_id;
SELECT SUM(salary), department_id, manager_id
FROM employees
GROUP BY department_id, manager_id;
Which SELECT clause allows you to restrict the rows returned, based on a group function?
♦HAVING salary > 100000
♦HAVING SUM(salary) > 100000 (*)
♦WHERE salary > 100000
♦WHERE SUM(salary) > 100000
♦HAVING SUM(salary) > 100000 (*)
♦WHERE salary > 100000
♦WHERE SUM(salary) > 100000
35. The PLAYERS and TEAMS tables contain these columns:
PLAYERS
PLAYER_ID NUMBER NOT NULL, PRIMARY KEY
LAST_NAME VARCHAR2 (30) NOT NULL
FIRST_NAME VARCHAR2 (25) NOT NULL
TEAM_ID NUMBER
POSITION VARCHAR2 (25)
PLAYERS
PLAYER_ID NUMBER NOT NULL, PRIMARY KEY
LAST_NAME VARCHAR2 (30) NOT NULL
FIRST_NAME VARCHAR2 (25) NOT NULL
TEAM_ID NUMBER
POSITION VARCHAR2 (25)
TEAMS
TEAM_ID NUMBER NOT NULL, PRIMARY KEY
TEAM_NAME VARCHAR2 (25)
TEAM_ID NUMBER NOT NULL, PRIMARY KEY
TEAM_NAME VARCHAR2 (25)
You need to create a report that lists the names of each team with more than three goal keepers.
Which SELECT statement will produce the desired result?
Which SELECT statement will produce the desired result?
♦SELECT t.team_name, COUNT(p.player_id)
FROM players p, teams t
ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = ‘GOAL KEEPER’
GROUP BY t.team_name
HAVING COUNT(p.player_id) > 3;
FROM players p, teams t
ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = ‘GOAL KEEPER’
GROUP BY t.team_name
HAVING COUNT(p.player_id) > 3;
♦SELECT t.team_name, COUNT(p.player_id)
FROM players p
JOIN teams t ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = ‘GOAL KEEPER’
GROUP BY t.team_name
HAVING COUNT(p.player_id) > 3;
(*)
FROM players p
JOIN teams t ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = ‘GOAL KEEPER’
GROUP BY t.team_name
HAVING COUNT(p.player_id) > 3;
(*)
♦SELECT t.team_name, COUNT(p.player_id)
FROM players
JOIN teams t ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = ‘GOAL KEEPER’
HAVING COUNT(p.player_id) > 3;
FROM players
JOIN teams t ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = ‘GOAL KEEPER’
HAVING COUNT(p.player_id) > 3;
♦SELECT t.team_name, COUNT(p.player_id)
FROM players p, teams t
ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = ‘GOAL KEEPER’
GROUP BY t.team_name;
FROM players p, teams t
ON (p.team_id = t.team_id)
WHERE UPPER(p.position) = ‘GOAL KEEPER’
GROUP BY t.team_name;
36. Evaluate this statement:
SELECT department_id, AVG(salary)
FROM employees
WHERE job_id <> 69879
GROUP BY job_id, department_id
HAVING AVG(salary) > 35000
ORDER BY department_id;
SELECT department_id, AVG(salary)
FROM employees
WHERE job_id <> 69879
GROUP BY job_id, department_id
HAVING AVG(salary) > 35000
ORDER BY department_id;
Which clauses restricts the result? Choose two.
(Choose all correct answers)
♦WHERE job_id <> 69879 (*)
♦SELECT department_id, AVG(salary)
♦HAVING AVG(salary) > 35000 (*)
♦GROUP BY job_id, department_id
♦WHERE job_id <> 69879 (*)
♦SELECT department_id, AVG(salary)
♦HAVING AVG(salary) > 35000 (*)
♦GROUP BY job_id, department_id
37. Examine the following statement:
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY GROUPING SETS((department_id, manager_id), (department_id, job_id))
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY GROUPING SETS((department_id, manager_id), (department_id, job_id))
What data will this query generate?
♦Sum of salaries for (department_id, job_id) and (department_id, manager_id) (*)
♦Sum of salaries for (department_id, job_id, manager_id)
♦Subtotals for (job_id, manager_id)
♦The statement will fail.
♦Sum of salaries for (department_id, job_id, manager_id)
♦Subtotals for (job_id, manager_id)
♦The statement will fail.
38. You use GROUPING functions to ______ database rows from tabulated rows.
♦COMPUTE
♦COUNT
♦DISTINGUISH (*)
♦CREATE
♦COUNT
♦DISTINGUISH (*)
♦CREATE
39. Examine the following statement:
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY GROUPING SETS(…….);
SELECT department_id, manager_id, job_id, SUM(salary)
FROM employees
GROUP BY GROUPING SETS(…….);
Select the correct GROUP BY GROUPING SETS clause from the following list:
♦GROUP BY GROUPING SETS ((department_id, manager_id), (department_id, job_id), (manager_id, job_id)) (*)
♦GROUP BY GROUPING SETS ((department_id, manager_id), (department_id, SUM(salary), (manager_id, job_id))
♦GROUP BY GROUPING SETS (department_id, AVG(salary)), (department_id, job_id), (department_id, manager_id)
♦GROUP BY GROUPING SETS (department_id, salary), (department_id, job_id), (department_id, manager_id)
40. CUBE can be applied to all aggregate functions including AVG, SUM, MIN, MAX, and COUNT. True or False?
♦True (*)
♦False
♦False
41. GROUPING SETS is another extension to the GROUP BY clause and is used to specify multiple groupings of data but provide a single result set. True or False?
♦True (*)
♦False
♦True (*)
♦False
42. If you want to include subtotals and grand totals for all columns mentioned in a GROUP BY clause, you should use which of the following extensions to the GROUP BY clause?
♦HAVING
♦ROLLUP
♦CUBE (*)
♦GROUP BY ALL COLUMNS
♦HAVING
♦ROLLUP
♦CUBE (*)
♦GROUP BY ALL COLUMNS
43. The ___________ operator returns all rows from both tables, after eliminating duplicates.
♦MINUS
♦UNION ALL
♦UNION (*)
♦INTERSECT
♦MINUS
♦UNION ALL
♦UNION (*)
♦INTERSECT
44. MINUS will give you rows from the first query that are not present in the second query. (True or False?)
♦True (*)
♦False
♦True (*)
♦False
45. When using SET operators, the number of columns and the data types of the columns must be identical in all of the SELECT statements used in the query. True or False.
♦True (*)
♦True (*)
♦False
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